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Proof step 28 from proof getarray-subset-02 (previous step)

¬ (st ⊆ st0 ∧ is_arrayref(r, i + j, st) ∧ 0 ≤ i), st ⊆ st0, is_array(r, st), i + j ≤ st[r -- _length] .intval, 0 ≤ i ⊦ getarray(r, i, j, st) = getarray(r, i, j, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
st ⊆ st0, is_array(r, st), i + j ≤ st[r -- _length] .intval, 0 ≤ i ⊦ getarray(r, i, j, st) = getarray(r, i, j, st0), is_arrayref(r, i + j, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i ≤ j → (¬ ¬ j < i ↔ false)], [CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i])]]