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Proof step 29 from proof getarray-subset-02 (previous step)

st ⊆ st0, is_array(r, st), i + j ≤ st[r -- _length] .intval, 0 ≤ i ⊦ getarray(r, i, j, st) = getarray(r, i, j, st0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ st ⊆ st0 ∧ is_arrayref(r, i + j, st) ∧ 0 ≤ i → getarray(r, i, j, st) = getarray(r, i, j, st0)
Proof step 28:
¬ (st ⊆ st0 ∧ is_arrayref(r, i + j, st) ∧ 0 ≤ i), st ⊆ st0, is_array(r, st), i + j ≤ st[r -- _length] .intval, 0 ≤ i ⊦ getarray(r, i, j, st) = getarray(r, i, j, st0)

Rule argument

[speclemmaarg: , st ⊆ st0 ∧ is_arrayref(r, i + j, st) ∧ 0 ≤ i → getarray(r, i, j, st) = getarray(r, i, j, st0) ,[st, st0, r, i, j] → [st, st0, r, i, j] ,F ,storearrays , ,getarray-subset ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, st0, r, i, j)]]