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Proof step 6 from proof infis-jvmref (previous step)

jvmref -- sk ∈ st, fis0 ∈ st, jvmref ∈ st, ∀ r, st, sk, val. r = jvmref ∨ (fis0 ∈ st[r -- sk, val] ↔ fis0 ∈ st) ⊦ r = jvmref, fis0 ∈ st[r -- sk0, val0]

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 4, [QUANTTERMLIST : (r, st, sk0, val0)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, st, sk0, val0)]]