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Proof step 7 from proof infis-jvmref (previous step)

jvmref -- sk ∈ st ∧ st[jvmref -- sk] = val ∧ fis0 ∈ st, ∀ r, st, sk, val. r = jvmref ∨ (fis0 ∈ st[r -- sk, val] ↔ fis0 ∈ st) ⊦ fis0 ∈ st[r -- sk0, val0] ∧ jvmref -- sk ∈ st ∧ st[jvmref -- sk] = val, r = jvmref

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st])]]