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Proof step 8 from proof infis-jvmref (previous step)

∀ r, st, sk, val. r = jvmref ∨ (fis0 ∈ st[r -- sk, val] ↔ fis0 ∈ st) ⊦ r = jvmref, fis0 ∈ st[r -- sk0, val0] ∧ jvmref -- sk ∈ st ∧ st[jvmref -- sk] = val ↔ jvmref -- sk ∈ st ∧ st[jvmref -- sk] = val ∧ fis0 ∈ st

User applied rule case distinction

And obtained the following new goals

Rule argument

[CASEDARG : pos: right 2, ()]

Additional information

[[CONCRETESIMPRULES : ()]]