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Proof step 2 from proof pseq-subset-01 (
previous step
)
⊦ ¬ cyclic(str, r, st) ∧ ¬ cyclic(str, r1, st1) ∧ ¬ junkref(str, r, st) ∧ ¬ junkref(str, r1, st1) → (ps=(r, st, r1, st1) ↔ ps=(r1, st1, r, st))
Lemma
pseq-sym