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Proof step 156 from proof addarray-disjoint-nosharing-01 (previous step)

vals[i→n(i0)] = refval(r2), vals[i→n(i)] = refval(r1), (addarray(r, ty, vals, st)[r -- (i ' ' + sks1)]) = refval(r0), (addarray(r, ty, vals, st)[r -- (i0 ' ' + sks)]) = refval(r0), i < n→i(# vals), newref(r, st), validreflist(str, vals, ty, st), disjoint(str, vals .nonnullrefs, st), i0 < n→i(# vals), 0 ≤ i, fits(r1, sks1, addarray(r, ty, vals, st)), is_referencevalue(vals[i→n(i0)]), fits(r2, sks, addarray(r, ty, vals, st)), 0 ≤ i0 ⊦ r0 = jvmref, vals = [], r = jvmref, i0 ' ' + sks = i ' ' + sks1, hasSharing(vals .nonnullrefs, st), dups(vals .nonnullrefs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 155:
(addarray(r, ty, vals, st)[r -- (i0 ' ' + sks)]) = refval(r0), (addarray(r, ty, vals, st)[r -- (i ' ' + sks1)]) = refval(r0), vals[i→n(i)] = refval(r1), vals[i→n(i0)] = refval(r2), 0 ≤ i0, fits(r2, sks, addarray(r, ty, vals, st)), fits(r1, sks1, addarray(r, ty, vals, st)), 0 ≤ i, i0 < n→i(# vals), disjoint(str, vals .nonnullrefs, st), validreflist(str, vals, ty, st), newref(r, st), i < n→i(# vals) ⊦ i0 ' ' + sks = i ' ' + sks1, r = jvmref, vals = [], r0 = jvmref, dups(vals .nonnullrefs), hasSharing(vals .nonnullrefs, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : javavalue, , test-19, ⊦ is_referencevalue(refval(r))])]]