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Proof step 157 from proof addarray-disjoint-nosharing-01 (previous step)

vals[i→n(i)] = refval(r1), (addarray(r, ty, vals, st)[r -- (i ' ' + sks1)]) = refval(r0), (addarray(r, ty, vals, st)[r -- (i0 ' ' + sks)]) = refval(r0), i < n→i(# vals), newref(r, st), validreflist(str, vals, ty, st), disjoint(str, vals .nonnullrefs, st), i0 < n→i(# vals), 0 ≤ i, fits(r1, sks1, addarray(r, ty, vals, st)), is_referencevalue(vals[i→n(i0)]), fits(vals[i→n(i0)] .refval, sks, addarray(r, ty, vals, st)), 0 ≤ i0 ⊦ r0 = jvmref, vals = [], r = jvmref, i0 ' ' + sks = i ' ' + sks1, hasSharing(vals .nonnullrefs, st), dups(vals .nonnullrefs)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

[x0lemmaarg: spec-name: javavalue instance-name: lemma-name: elim-13 antecedent: succedent: is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) substlist: [val, r] → [vals[i→n(i0)], r2] add preconditions?: F is rewrite lemma?: F current spec?: F rotate lemma?: T replace all?: T paths: () dummy: () ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (vals[i→n(i0)], r2)]]