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Proof step 15 from proof fits-append (previous step)

∀ r, sks0, st. fits(r, sks1 + sks0, st) ↔ fits(r, sks1, st) ∧ fits(st[r -- sks1] .refval, sks0, st) ⊦ sks1 = [], r ≠ jvmref ∧ is_referencevalue(st[r -- sk]) ∧ (is_classtype(st[r -- _type] .type) → sk ∈ instfields(st[r -- _type] .type .class)) ∧ (is_arraytype(st[r -- _type] .type) → is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < st[r -- _length] .intval) ∧ fits(st[r -- sk] .refval, sks1 + sks0, st) ↔ r ≠ jvmref ∧ is_referencevalue(st[r -- sk]) ∧ (is_classtype(st[r -- _type] .type) → sk ∈ instfields(st[r -- _type] .type .class)) ∧ (is_arraytype(st[r -- _type] .type) → ¬ is_fskey(sk) ∧ ¬ sk .index < 0 ∧ ¬ st[r -- _length] .intval ≤ sk .index) ∧ fits(st[r -- sk] .refval, sks1, st) ∧ fits(st[st[r -- sk] .refval -- sks1] .refval, sks0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
is_referencevalue(st[r -- sk]), ∀ r, sks0, st. fits(r, sks1 + sks0, st) ↔ fits(r, sks1, st) ∧ fits(st[r -- sks1] .refval, sks0, st), is_classtype(st[r -- _type] .type) → sk ∈ instfields(st[r -- _type] .type .class) ⊦ sks1 = [], (is_arraytype(st[r -- _type] .type) → is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < st[r -- _length] .intval) ∧ fits(st[r -- sk] .refval, sks1 + sks0, st) ↔ (is_arraytype(st[r -- _type] .type) → ¬ is_fskey(sk) ∧ ¬ sk .index < 0 ∧ ¬ st[r -- _length] .intval ≤ sk .index) ∧ fits(st[r -- sk] .refval, sks1, st) ∧ fits(st[st[r -- sk] .refval -- sks1] .refval, sks0, st), r = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]