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Proof step 34 from proof fits-in (previous step)

st[r -- sk] = refval(r1), is_array(str, r, st), r ∈ st, r -- sk ∈ st, fits(r1, sks0, st), is_arraytype(st[r -- _type] .type), is_indexkey(sk), sk .index < st[r -- _length] .intval, 0 ≤ sk .index, 0 < st[r -- _length] .intval, ∀ str0, r0, st0. ¬ junkref(str0, r0, st0) ∧ fits(r0, sks0, st0) → r0 -- sks0 ∈ st0 ⊦ r = jvmref, sks0 = [], r1 -- sks0 ∈ st, junkref(str, r, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 33:
sk = i ', st[r -- sk] = refval(r1), is_array(str, r, st), r ∈ st, r -- sk ∈ st, fits(r1, sks0, st), is_arraytype(st[r -- _type] .type), is_indexkey(sk), i < st[r -- _length] .intval, 0 ≤ i, 0 < st[r -- _length] .intval, ∀ str0, r0, st0. ¬ junkref(str0, r0, st0) ∧ fits(r0, sks0, st0) → r0 -- sks0 ∈ st0 ⊦ r = jvmref, sks0 = [], r1 -- sks0 ∈ st, junkref(str, r, st)

Rule argument

[speclemmaarg: ,is_indexkey(sk) → (i = sk .index ↔ sk = i ') ,[sk, i] → [sk, i] ,T ,storekey , ,elim-04 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_indexkey(sk) → (i = sk .index ↔ sk = i ')])], [EXTRATERMS : (sk, i)]]