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Proof step 11 from proof arrayref (conclusion)

⊦ is_arrayref(r, i, st[r0 -- fs ', val]) ↔ is_arrayref(r, i, st)

Heuristic pl case distinction applied rule case distinction

And obtained the following new goals

Proof step 7:
is_arrayref(r, i, st[r0 -- fs ', val]) ⊦ is_arrayref(r, i, st)
Proof step 10:
is_arrayref(r, i, st) ⊦ is_arrayref(r, i, st[r0 -- fs ', val])

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]