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Proof step 7 from proof arrayref (previous step)

is_arrayref(r, i, st[r0 -- fs ', val]) ⊦ is_arrayref(r, i, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ is_arrayref(r, i, st) ↔ (∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ st)
Proof step 6:
is_arrayref(r, i, st[r0 -- fs ', val]) ⊦ ∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ st

Rule argument

[crewrite-arg: is_arrayref, F, [st, i, r] → [st, i, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, i, r)]]