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Proof step 6 from proof arrayref (previous step)

is_arrayref(r, i, st[r0 -- fs ', val]) ⊦ ∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
j < i, is_arrayref(r, i, st[r0 -- fs ', val]), 0 ≤ j, 0 < i ⊦ r -- j ' ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j])]]