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Proof step 5 from proof arrayref (previous step)

j < i, is_arrayref(r, i, st[r0 -- fs ', val]), 0 ≤ j, 0 < i ⊦ r -- j ' ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ is_arrayref(r, i, st) ↔ (∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ st)
Proof step 4:
j < i, ∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ st[r0 -- fs ', val], 0 ≤ j, 0 < i ⊦ r -- j ' ∈ st

Rule argument

[crewrite-arg: is_arrayref , F , [st, i, r] → [st[r0 -- fs ', val], i, r] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st[r0 -- fs ', val], i, r)]]