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Proof step 21 from proof bar-sublist (previous step)

n→i(n) ≤ i0, 0 ≤ i0 ⊦ sublist(m, n, getbytearray(r, i, n→i(m), st) + getbytearray(r, i + n→i(m), i0, st)) = getbytearray(r, i + n→i(m), n→i(n), st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ # bytes ≤ n → sublist(n, m, bytes + bytes0) = sublist(n - # bytes, m, bytes0)
Proof step 4:
¬ # getbytearray(r, i, n→i(m), st) ≤ m, n→i(n) ≤ i0, 0 ≤ i0 ⊦ sublist(m, n, getbytearray(r, i, n→i(m), st) + getbytearray(r, i + n→i(m), i0, st)) = getbytearray(r, i + n→i(m), n→i(n), st)
Proof step 20:
# getbytearray(r, i, n→i(m), st) ≤ m, n→i(n) ≤ i0, 0 ≤ i0 ⊦ sublist(m - # getbytearray(r, i, n→i(m), st), n, getbytearray(r, i + n→i(m), i0, st)) = getbytearray(r, i + n→i(m), n→i(n), st)

Rule argument

[speclemmaarg: , # bytes ≤ n → sublist(n, m, bytes + bytes0) = sublist(n - # bytes, m, bytes0) ,[bytes0, bytes, m, n] → [getbytearray(r, i + n→i(m), i0, st), getbytearray(r, i, n→i(m), st), n, m] ,F ,list-del ,bytelist ,sublist-append-01 ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (getbytearray(r, i + n→i(m), i0, st), getbytearray(r, i, n→i(m), st), n, m)]]