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Proof step 4 from proof bar-sublist (previous step)

¬ # getbytearray(r, i, n→i(m), st) ≤ m, n→i(n) ≤ i0, 0 ≤ i0 ⊦ sublist(m, n, getbytearray(r, i, n→i(m), st) + getbytearray(r, i + n→i(m), i0, st)) = getbytearray(r, i + n→i(m), n→i(n), st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ # getbytearray(r, i, n→i(m), st) = m

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ n < n], [CSIMPSEQ : ⊦ ¬ m ≤ n ↔ n < m])]]