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Proof step 3 from proof copy-arref (previous step)

j < i1, 0 ≤ j, 0 < i1, ∀ j0. ¬ j0 < 0 ∧ ¬ i1 ≤ j0 → r1 -- j0 ' ∈ st ⊦ r1 = r0, r1 -- j ' ∈ st

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 4, [QUANTTERMLIST : (j)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i ≤ j → (¬ ¬ j < i ↔ false)], [CSIMPSEQ : ⊦ i < j → (¬ ¬ j ≤ i ↔ false)])], [EXTRATERMS : (j)]]