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Proof step 4 from proof copy-arref (previous step)

∀ j0. ¬ j0 < 0 ∧ ¬ i1 ≤ j0 → r1 -- j0 ' ∈ st ⊦ ∀ j. 0 ≤ j ∧ j < i1 → r1 -- j ' ∈ st, r1 = r0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j < i1, 0 ≤ j, 0 < i1, ∀ j0. ¬ j0 < 0 ∧ ¬ i1 ≤ j0 → r1 -- j0 ' ∈ st ⊦ r1 = r0, r1 -- j ' ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j])]]