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Proof step 21 from proof getarray-in-01 (previous step)

i1 = i3 + 1, i < i0 + i1, i0 ≤ i, 1 < i1, 0 < i1, ∀ r, st, i, i0, i2. i→n(i2) < i→n(i1) → (i0 ≤ i ∧ i < i0 + i2 ∧ 0 < i2 → st[r -- i '] ∈ getarray(r, i0, i2, st)) ⊦ st[r -- i '] = st[r -- (i0 + i1 - 1) '], st[r -- i '] ∈ getarray(r, i0, i3, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
i0 ≤ i, i ≤ i0 + i3, 0 < i3, 0 ≤ i3, ∀ r, st, i, i0, i2. i→n(i2) < i→n(i3 + 1) → (i0 ≤ i ∧ i < i0 + i2 ∧ 0 < i2 → st[r -- i '] ∈ getarray(r, i0, i2, st)) ⊦ st[r -- i '] = st[r -- (i0 + i3) '], st[r -- i '] ∈ getarray(r, i0, i3, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPSEQ : ⊦ i ≤ i + j ↔ 0 ≤ j], [CSIMPFORWARD : ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1], [CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j], [CSIMPSEQ : ⊦ 0 < i ∧ 0 < j → 0 < i + j], [CSIMPSEQ : ⊦ ((* j)) < i0 + ((* j0)) ↔ j - j0 < i0], [CSIMPSEQ : ⊦ i < j + 1 ↔ i ≤ j], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + 0 = i], [CSIMPSEQ : ⊦ ((* i)) + i0 - ((* j)) = (i - j) + i0])]]