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Proof step 22 from proof getarray-in-01 (previous step)

i < i0 + i1, i0 ≤ i, 1 < i1, 0 < i1, ∀ r, st, i, i0, i2. i→n(i2) < i→n(i1) → (i0 ≤ i ∧ i < i0 + i2 ∧ 0 < i2 → st[r -- i '] ∈ getarray(r, i0, i2, st)) ⊦ st[r -- i '] = st[r -- (i0 + i1 - 1) '], st[r -- i '] ∈ getarray(r, i0, i1 - 1, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 21:
i1 = i3 + 1, i < i0 + i1, i0 ≤ i, 1 < i1, 0 < i1, ∀ r, st, i, i0, i2. i→n(i2) < i→n(i1) → (i0 ≤ i ∧ i < i0 + i2 ∧ 0 < i2 → st[r -- i '] ∈ getarray(r, i0, i2, st)) ⊦ st[r -- i '] = st[r -- (i0 + i1 - 1) '], st[r -- i '] ∈ getarray(r, i0, i3, st)

Rule argument

[speclemmaarg: ,i0 = i - j ↔ i = i0 + j ,[i, j, i0] → [i1, 1, i3] ,T ,int-abs , ,elim-sub ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ i0 = i - j ↔ i = i0 + j])], [EXTRATERMS : (i1, 1, i3)]]