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Proof step 12 from proof getarray-put-03 (previous step)

1 < j, 0 < j, ∀ j0, r, i, st, r0, fs, val. i→n(j0) < i→n(j) → (true → getarray(r, i, j0, st[r0 -- fs ', val]) = getarray(r, i, j0, st)) ⊦ getarray(r, i, j - 1, st[r0 -- fs ', val]) + st[r -- (i + j - 1) '] ' = getarray(r, i, j, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
j = i0 + 1, 1 < j, 0 < j, ∀ j0, r, i, st, r0, fs, val. i→n(j0) < i→n(j) → (true → getarray(r, i, j0, st[r0 -- fs ', val]) = getarray(r, i, j0, st)) ⊦ getarray(r, i, i0, st[r0 -- fs ', val]) + st[r -- (i + j - 1) '] ' = getarray(r, i, j, st)

Rule argument

[speclemmaarg: ,i0 = i - j ↔ i = i0 + j ,[i, j, i0] → [j, 1, i0] ,T ,int-abs , ,elim-sub ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ i0 = i - j ↔ i = i0 + j])], [EXTRATERMS : (j, 1, i0)]]