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Proof step 13 from proof getarray-put-03 (previous step)

1 < j, ∀ j0, r, i, st, r0, fs, val. i→n(j0) < i→n(j) → (true → getarray(r, i, j0, st[r0 -- fs ', val]) = getarray(r, i, j0, st)) ⊦ getarray(r, i, j - 1, st[r0 -- fs ', val]) + (st[r0 -- fs ', val][r -- (i + j - 1) ']) = getarray(r, i, j, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
1 < j, 0 < j, ∀ j0, r, i, st, r0, fs, val. i→n(j0) < i→n(j) → (true → getarray(r, i, j0, st[r0 -- fs ', val]) = getarray(r, i, j0, st)) ⊦ getarray(r, i, j - 1, st[r0 -- fs ', val]) + st[r -- (i + j - 1) '] ' = getarray(r, i, j, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j], [CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j], [CSIMPSEQ : ⊦ vals + val = vals + val '], [CSIMPSEQ : ⊦ fs ' ≠ i '], [CSIMPSEQ : ⊦ r -- sk = r0 -- sk0 ↔ ¬ ¬ (r = r0 ∧ sk = sk0)], [CSIMPSEQ : ⊦ (st[rk0, val][rk]) = ((rk = rk0 ⊃ val; st[rk]))])]]