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Proof step 10 from proof getarray-subset (previous step)

st ⊆ st0, 0 ≤ i, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ getarray(r, i, j, st) = getarray(r, i, j, st0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ getarray(r, i, j, st) = getarray(r0, i0, j, st0) ↔ (∀ j0. 0 ≤ j0 ∧ j0 < j → st[r -- (i + j0) '] = st0[r0 -- (i0 + j0) '])
Proof step 9:
st ⊆ st0, 0 ≤ i, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ ∀ j0. 0 ≤ j0 ∧ j0 < j → st[r -- (i + j0) '] = st0[r -- (i + j0) ']

Rule argument

[crewrite-arg: get-alleq , F , [st0, i0, r0, st, j, i, r] → [st0, i, r, st, j, i, r] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st0, i, r, st, j, i, r)]]