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Proof step 9 from proof getarray-subset (previous step)

st ⊆ st0, 0 ≤ i, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ ∀ j0. 0 ≤ j0 ∧ j0 < j → st[r -- (i + j0) '] = st0[r -- (i + j0) ']

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
j0 < j, st ⊆ st0, 0 ≤ i, 0 ≤ j0, 0 < j, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ st[r -- (i + j0) '] = st0[r -- (i + j0) ']

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j])]]