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Proof step 8 from proof getarray-subset (previous step)

j0 < j, st ⊆ st0, 0 ≤ i, 0 ≤ j0, 0 < j, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ st[r -- (i + j0) '] = st0[r -- (i + j0) ']

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ rk ∈ st ∧ st ⊆ st1 → st[rk] = st1[rk]
Proof step 7:
¬ (r -- (i + j0) ' ∈ st ∧ st ⊆ st0), j0 < j, st ⊆ st0, 0 ≤ i, 0 ≤ j0, 0 < j, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ st[r -- (i + j0) '] = st0[r -- (i + j0) ']

Rule argument

[speclemmaarg: ,rk ∈ st ∧ st ⊆ st1 → st[rk] = st1[rk] ,[rk, st, st1] → [r -- (i + j0) ', st, st0] ,F ,store ,javastore ,subset-elem-eq ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j = j + i])], [EXTRATERMS : (r -- (i + j0) ', st, st0)]]