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Proof step 4 from proof getarray-subset (previous step)

j0 < j, st ⊆ st0, 0 ≤ i, 0 ≤ j0, 0 < j, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ noval = st0[r -- (i + j0) '], r -- (i + j0) ' ∈ st

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 6, [extquanttermlist: (i + j0)abort:F, discard:F, computed:T]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ 0 ≤ i ∧ 0 ≤ j → ¬ i + j < 0], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + j ≤ i0 + j ↔ i ≤ i0], [CSIMPSEQ : ⊦ i < j → (¬ ¬ j ≤ i ↔ false)])], [EXTRATERMS : (i + j0)]]