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Proof step 5 from proof getarray-subset (previous step)

j0 < j, st ⊆ st0, 0 ≤ i, 0 ≤ j0, 0 < j, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ r -- (i + j0) ' ∈ st, st[r -- (i + j0) '] = st0[r -- (i + j0) ']

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
j0 < j, st ⊆ st0, 0 ≤ i, 0 ≤ j0, 0 < j, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ noval = st0[r -- (i + j0) '], r -- (i + j0) ' ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ ∅[rk] = noval], [CSIMPSEQ : ⊦ ¬ rk ∈ st → st[rk] = ∅[rk]])]]