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Proof step 10 from proof getintarray-subset (previous step)

r -- _length ∈ st ∧ st ⊆ st0, st ⊆ st0, r -- _length ∈ st, r ∈ st, ∀ j. ¬ j < 0 ∧ ¬ st0[r -- _length] .intval ≤ j → r -- j ' ∈ st ⊦ getintarray(r, 0, st0[r -- _length] .intval, st) = getintarray(r, 0, st0[r -- _length] .intval, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
r ∈ st, r -- _length ∈ st, st ⊆ st0, ∀ j. ¬ j < 0 ∧ ¬ st0[r -- _length] .intval ≤ j → r -- j ' ∈ st ⊦ getintarray(r, 0, st0[r -- _length] .intval, st) = getintarray(r, 0, st0[r -- _length] .intval, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]