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Proof step 11 from proof getintarray-subset (previous step)

st ⊆ st0, r -- _length ∈ st, r ∈ st, ∀ j. ¬ j < 0 ∧ ¬ st[r -- _length] .intval ≤ j → r -- j ' ∈ st ⊦ getintarray(r, 0, st[r -- _length] .intval, st) = getintarray(r, 0, st0[r -- _length] .intval, st0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ rk ∈ st ∧ st ⊆ st1 → st[rk] = st1[rk]
Proof step 10:
r -- _length ∈ st ∧ st ⊆ st0, st ⊆ st0, r -- _length ∈ st, r ∈ st, ∀ j. ¬ j < 0 ∧ ¬ st0[r -- _length] .intval ≤ j → r -- j ' ∈ st ⊦ getintarray(r, 0, st0[r -- _length] .intval, st) = getintarray(r, 0, st0[r -- _length] .intval, st0)

Rule argument

[speclemmaarg: ,rk ∈ st ∧ st ⊆ st1 → st[rk] = st1[rk] ,[rk, st, st1] → [r -- _length, st, st0] ,F ,store ,javastore ,subset-elem-eq ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r -- _length, st, st0)]]