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Proof step 10 from proof putArray-put-switch-02 (conclusion)

⊦ is_fskey(sk) ∨ r0 ≠ r → putArray(vals, r, i, st[r0 -- sk, val]) = (putArray(vals, r, i, st)[r0 -- sk, val])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
is_fskey(sk) ∨ r0 ≠ r ⊦ putArray(vals, r, i, st[r0 -- sk, val]) = (putArray(vals, r, i, st)[r0 -- sk, val])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]