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Proof step 9 from proof putArray-put-switch-02 (previous step)

is_fskey(sk) ∨ r0 ≠ r ⊦ putArray(vals, r, i, st[r0 -- sk, val]) = (putArray(vals, r, i, st)[r0 -- sk, val])

User applied rule structural induction

And obtained the following new goals

Proof step 1:
⊦ putArray([], r, i, st) = st
Proof step 8:
∀ sk, r0, r, i, st, val. is_fskey(sk) ∨ r0 ≠ r → putArray(vals0, r, i, st[r0 -- sk, val]) = (putArray(vals0, r, i, st)[r0 -- sk, val]), is_fskey(sk) ∨ r0 ≠ r ⊦ putArray(val0 + vals0, r, i, st[r0 -- sk, val]) = (putArray(val0 + vals0, r, i, st)[r0 -- sk, val])

Rule argument

[VARWITHVARSEQSARG : vals, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : javavalues generated by [], +;])]]