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Proof step 14 from proof putarray-subset-new-01 (previous step)

r0 ∈ st, st ⊆ st0, r0 -- sk ∈ st, r0 -- sk ∈ st0, r0 ∈ st0 ⊦ st[r0 -- sk] = (putArray(vals, r, i, st0)[r0 -- sk]), r ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[crewrite-arg: putar-atref , F , [sk, r0, st, j, r, vals] → [sk, r0, st0, i, r, vals] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rk ∈ st ∧ st ⊆ st1 → (st[rk] ≠ st1[rk] ↔ false)])], [EXTRATERMS : (sk, r0, st0, i, r, vals)]]