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Proof step 15 from proof putarray-subset-new-01 (previous step)

rk = r0 -- sk, rk ∈ st, st ⊆ st0 ⊦ r ∈ st, (rk ∈ st0 ∨ r0 = r ∧ ¬ is_fskey(sk) ∧ ¬ sk .index < i ∧ ¬ i + n→i(# vals) ≤ sk .index) ∧ st[rk] = (putArray(vals, r, i, st0)[rk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
r0 ∈ st, st ⊆ st0, r0 -- sk ∈ st, r0 -- sk ∈ st0, r0 ∈ st0 ⊦ st[r0 -- sk] = (putArray(vals, r, i, st0)[r0 -- sk]), r ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rk ∈ st ∧ ¬ rk ∈ st0 → ¬ st ⊆ st0], [CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st])]]