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Theorem lookup-put-other
⊦ ¬ (∃ sks0, sks1. sks = sks0 + (sk + sks1) ∧ st[r -- sks0] .refval = r0 ∧ (∀ sks2. sks2 + sk ⊑ sks0 → st[r -- sks2] .refval ≠ r0)) → (st[r0 -- sk, val][r -- sks]) = st[r -- sks]
Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
Used by units in proved state:
Proof exists?: Yes
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the proof
Infos about the proof
Proved?: Yes
Interactions: 2
Proof steps: 6
Used lemmas:
lookup-put-ex-first
,
Used spec theorems:
Used simplifier rules:
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