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Proof step 35 from proof newrefs-new-01 (previous step)

∀ st. is_newref_list(newref_list(m, st), st), ¬ is_newref_list(newref_list(m, st[newref(st) -- 0 ', noval]), st) ∨ newref(st) ∈ newref_list(m, st[newref(st) -- 0 ', noval]) ⊦

User applied rule case distinction

And obtained the following new goals

Proof step 31:
¬ is_newref_list(newref_list(m, st[newref(st) -- 0 ', noval]), st), ∀ st. is_newref_list(newref_list(m, st), st) ⊦
Proof step 34:
newref(st) ∈ newref_list(m, st[newref(st) -- 0 ', noval]), ∀ st. is_newref_list(newref_list(m, st), st) ⊦

Rule argument

[CASEDARG : pos: left 2, ()]

Additional information

[[CONCRETESIMPRULES : ()]]