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Proof step 36 from proof newrefs-new-01 (previous step)

∀ st. is_newref_list(newref_list(m, st), st) ⊦ is_newref_list(newref_list(m +1, st), st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ newref_list(n + 1, st) = newref(st) + newref_list(n, st[newref(st) -- 0 ', noval])
Proof step 4:
⊦ is_newref_list(r ' + refs, st) ↔ ¬ ¬ (¬ r ∈ refs ∧ newref(r, st) ∧ is_newref_list(refs, st))
Proof step 5:
⊦ newref(newref(st), st)
Proof step 35:
∀ st. is_newref_list(newref_list(m, st), st), ¬ is_newref_list(newref_list(m, st[newref(st) -- 0 ', noval]), st) ∨ newref(st) ∈ newref_list(m, st[newref(st) -- 0 ', noval]) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ r + refs = r ' + refs], [CSIMPSEQ : ⊦ m +1 = m + 1])]]