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Proof step 4 from proof newrefs-one-01 (previous step)

newref_list(0 + 1, st) = newref(st) + newref_list(0, st[newref(st) -- 0 ', noval]) ⊦ newref_list(1, st) = newref(st) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
newref_list(1, st) = newref(st) ' + newref_list(0, st[newref(st) -- 0 ', noval]), newref(st) ∈ newref_list(1, st) ⊦ newref_list(1, st) = newref(st) '

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPFORWARD : ⊦ r ' + refs = refs0 → r ∈ refs0], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]