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Proof step 5 from proof newrefs-one-01 (conclusion)

⊦ newref_list(1, st) = newref(st) '

User applied rule insert lemma

And obtained the following new goals

Proof step 1:
⊦ newref_list(n + 1, st) = newref(st) + newref_list(n, st[newref(st) -- 0 ', noval])
Proof step 4:
newref_list(0 + 1, st) = newref(st) + newref_list(0, st[newref(st) -- 0 ', noval]) ⊦ newref_list(1, st) = newref(st) '

Rule argument

[LEMMAARG : newrefs-succ, [n, st] → [0, st]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (0, st)]]