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Proof step 25 from proof newrefs-rec (previous step)

⊦ is_newref_list(r ' + refs, st) ↔ ¬ r ∈ refs ∧ newref(r, st) ∧ is_newref_list(refs, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ is_newref_list(refs, st) ↔ ¬ dups(refs) ∧ (∀ r. r ∈ refs → newref(r, st))
Proof step 24:
⊦ ¬ dups(r ' + refs) ∧ (∀ r0. r0 ∈ r ' + refs → newref(r0, st)) ↔ ¬ r ∈ refs ∧ newref(r, st) ∧ is_newref_list(refs, st)

Rule argument

[crewrite-arg: list_ok, F, [st, refs] → [st, r ' + refs]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r ' + refs)]]