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Proof step 26 from proof newrefs-rec (conclusion)

⊦ is_newref_list(r ' + refs, st) ↔ ¬ ¬ (¬ r ∈ refs ∧ newref(r, st) ∧ is_newref_list(refs, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]