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Proof step 8 from proof newrefs-rec (previous step)

∀ r0. r0 ∈ refs ∨ r0 = r → r0 ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r0) ⊦ r ∈ refs, dups(refs), (r0 ∈ refs → newref(r0, st)) ∧ newref(r, st)

User applied rule all left

And obtained the following new goals

Proof step 7:
r ∈ refs ∨ r = r → r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r), ∀ r0. r0 ∈ refs → r0 ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r0) ⊦ r ∈ refs, dups(refs), (r0 ∈ refs → newref(r0, st)) ∧ newref(r, st)

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (r)abort:F, discard:F, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r)]]