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Proof step 9 from proof newrefs-rec (previous step)

¬ dups(refs) ∧ ¬ r ∈ refs ∧ (∀ r0. r0 ∈ refs ∨ r0 = r → r0 ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r0)) ⊦ ¬ r ∈ refs ∧ newref(r, st) ∧ ¬ dups(refs) ∧ (∀ r. r ∈ refs → newref(r, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
∀ r0. r0 ∈ refs ∨ r0 = r → r0 ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r0) ⊦ r ∈ refs, dups(refs), (r0 ∈ refs → newref(r0, st)) ∧ newref(r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]