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Proof step 7 from proof subset-newref (previous step)

st ⊆ st0, newref(r, st0) ⊦ r = jvmref, newref(r, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ newref(r, st) ↔ r ≠ jvmref ∧ ¬ r ∈ st
Proof step 6:
st ⊆ st0, r ≠ jvmref ∧ ¬ r ∈ st0 ⊦ r = jvmref, newref(r, st)

Rule argument

[crewrite-arg: newref-def, F, [st, r] → [st0, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st0, r)]]