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Proof step 8 from proof subset-newref (conclusion)

⊦ ¬ newref(r, st) ∧ newref(r, st0) → ¬ st ⊆ st0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ newref(r, st) → r ≠ jvmref
Proof step 7:
st ⊆ st0, newref(r, st0) ⊦ r = jvmref, newref(r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]