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Theorem eqobj
⊦ eqobj(r, st, st0) ↔ (∀ sk. (r -- sk ∈ st ↔ r -- sk ∈ st0) ∧ st[r -- sk] = st0[r -- sk])
Type: An axiom
Validity: The proof is valid.
Features:
Comment:
Used by:
Used by units in proved state:
Proof exists?: No