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Proof step 3 from proof refp-01 (previous step)

is_referencevalue(val) ∧ val .refval ≠ jvmref ⊦ refval(val .refval) = val

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
is_referencevalue(val) ⊦ val .refval = jvmref, refval(val .refval) = val

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]