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Proof step 4 from proof refp-01 (previous step)

refp(val) ⊦ refval(val .refval) = val

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ refp(val) ↔ is_referencevalue(val) ∧ val .refval ≠ jvmref
Proof step 3:
is_referencevalue(val) ∧ val .refval ≠ jvmref ⊦ refval(val .refval) = val

Rule argument

[crewrite-arg: refp, F, [val] → [val]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (val)]]