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Proof step 14 from proof stringval (previous step)

∀ val. flatten(val ++ stringval(stringvar)) = flatten(val) ++ stringval(stringvar) ⊦ flatten(val ++ stringval(char0 + stringvar)) = val ++ stringval(char0 + stringvar), is_valuelist(val)

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 12:
⊦ ¬ is_valuelist(val0) → flatten(val ++ val0) = flatten(val) ++ val0
Proof step 13:
⊦ ¬ is_valuelist(val) → flatten(val) = val

Rule argument

[fma-arg: is_valuelist(stringval(char0 + stringvar))]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ is_valuelist (stringval(stringvar))], [CSIMPSEQ : ⊦ val ++ val1 = val0 ++ val1 ↔ val = val0])], [EXTRAFMAS : (is_valuelist(stringval(char0 + stringvar)))]]