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Proof step 15 from proof stringval (previous step)

∀ val. flatten(val ++ stringval(stringvar)) = flatten(val) ++ stringval(stringvar) ⊦ is_valuelist(val), flatten(val ++ stringval(char0 + stringvar)) = flatten(val) ++ stringval(char0 + stringvar)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
⊦ ¬ is_valuelist(val) → flatten(val) = val
Proof step 14:
∀ val. flatten(val ++ stringval(stringvar)) = flatten(val) ++ stringval(stringvar) ⊦ flatten(val ++ stringval(char0 + stringvar)) = val ++ stringval(char0 + stringvar), is_valuelist(val)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]