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Proof step 16 from proof stringval (previous step)

∀ val. flatten(val ++ stringval(stringvar)) = flatten(val) ++ stringval(stringvar) ⊦ flatten(val ++ stringval(char0 + stringvar)) = flatten(val) ++ stringval(char0 + stringvar)

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 10:
is_valuelist(val), ∀ val. flatten(val ++ stringval(stringvar)) = flatten(val) ++ stringval(stringvar) ⊦ flatten(val ++ stringval(char0 + stringvar)) = flatten(val) ++ stringval(char0 + stringvar)
Proof step 15:
∀ val. flatten(val ++ stringval(stringvar)) = flatten(val) ++ stringval(stringvar) ⊦ is_valuelist(val), flatten(val ++ stringval(char0 + stringvar)) = flatten(val) ++ stringval(char0 + stringvar)

Rule argument

[fma-arg: is_valuelist(val)]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (is_valuelist(val))]]